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我女儿的题目
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15少 -
♂
(88 bytes)
()
05/27/2011
09:22:06
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Is this the correct question?
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Pantsonfire -
(34 bytes)
()
05/28/2011
20:22:45
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N-->N, from natural to natural
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15少 -
♂
(0 bytes)
()
05/29/2011
01:24:18
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Dom't worry,next year the question being changed to f(f(x))=n+ 2
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jinjing -
(226 bytes)
()
05/29/2011
08:57:40
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no such relation neither
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15少 -
♂
(0 bytes)
()
05/31/2011
15:56:33
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Can you give the proof? If you can't show , and then I contruct
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jinjing -
(0 bytes)
()
05/31/2011
18:10:49
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c
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15少 -
♂
(681 bytes)
()
06/01/2011
03:34:14
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What is relation? your 1 to 6 is just my proof. my 2011/2 out of
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jinjing -
(255 bytes)
()
06/01/2011
06:51:04
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回复:What is relation? your 1 to 6 is just my proof. my 2011/2 out
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15少 -
♂
(133 bytes)
()
06/01/2011
08:31:32
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your (2) means f is bijection function. 1 to 1 and onto.
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jinjing -
(78 bytes)
()
06/01/2011
09:03:44
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回复:your (2) means f is bijection function. 1 to 1 and onto.
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15少 -
♂
(47 bytes)
()
06/01/2011
09:19:59
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If f is linear, OK. But we can't say nonlinear f is impossible b
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jinjing -
(45 bytes)
()
06/01/2011
11:41:54
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you said yourself "for any f, no solution"
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15少 -
♂
(41 bytes)
()
06/01/2011
13:14:55
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回复:you said yourself "for any f, no solution"
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jinjing -
(55 bytes)
()
06/01/2011
14:28:17
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is there anything wrong in my demonstration 1) to 6)?
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15少 -
♂
(0 bytes)
()
06/01/2011
15:06:40
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your answer is not math answer, I do this Q, I hope...
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jinjing -
(191 bytes)
()
06/02/2011
10:07:19
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MY answer is MY math answer.
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15少 -
♂
(299 bytes)
()
06/02/2011
12:41:02
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I like the people who like Math. Let me...
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jinjing -
(177 bytes)
()
06/02/2011
15:51:05
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回复:I like math, not myth nor...
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15少 -
♂
(266 bytes)
()
06/02/2011
17:24:06
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You at first you don't...
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jinjing -
(164 bytes)
()
06/02/2011
18:23:04
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回复:What is relation? your 1 to 6 is just my proof. my 2011/2 out
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jinjing -
(0 bytes)
()
04/24/2012
08:11:12
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Nice!
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乱弹 -
♂
(0 bytes)
()
06/01/2011
18:40:26
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thanks!
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15少 -
♂
(0 bytes)
()
06/02/2011
12:46:16
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回复:c Could you provide some details for
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wxcfan123 -
♂
(247 bytes)
()
06/11/2011
18:57:48
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figure out missing details. Nice problem and nice solution.
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wxcfan123 -
♂
(335 bytes)
()
06/12/2011
14:36:53
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回复:我女儿的题目
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letmeregister -
♂
(555 bytes)
()
06/04/2011
20:46:08
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回复:我女儿的题目
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alladin -
♂
(883 bytes)
()
07/08/2011
23:34:44
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Putnam 题(2星)
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康MM -
♀
(90 bytes)
()
05/26/2011
09:54:37
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4
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jinjing -
(0 bytes)
()
05/26/2011
15:48:54
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3.14 - 偶尔路过这里,没想到我能答这题
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拖拉机手 -
♂
(0 bytes)
()
06/08/2011
18:18:48
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2
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jinjing -
(0 bytes)
()
06/09/2011
20:04:54
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玩笑
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jinjing -
(0 bytes)
()
06/09/2011
20:11:53
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您的圆内接正方形,面积是2,但半径不是1.不是说您2.
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jinjing -
(0 bytes)
()
06/13/2011
18:55:11
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做不出来,是不是可以公布答案啦?
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砂锅2 -
♂
(0 bytes)
()
06/15/2011
19:21:27
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答案是4.突域其实是4边形.
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jinjing -
(354 bytes)
()
06/16/2011
06:17:05
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行列式早就忘记了,这个四元表达式的最小值怎么计算?
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砂锅2 -
♂
(0 bytes)
()
06/17/2011
21:13:50
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N边形面积可由N个二階行列式之和之半表达
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jinjing -
(213 bytes)
()
06/18/2011
06:05:54
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说个几何逻辑的解法
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说了就走 -
♂
(282 bytes)
()
06/29/2011
09:02:59
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BD过原点O且被O平分,不严格.
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jinjing -
(0 bytes)
()
06/29/2011
15:12:36
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因为BD对O旋转对称
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说了就走 -
♂
(0 bytes)
()
06/29/2011
23:14:19
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您的ABCD是任取的,BD不一定过O点...过O点要证明.
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jinjing -
(0 bytes)
()
06/30/2011
08:04:12
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您恐怕没看懂
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说了就走 -
♂
(234 bytes)
()
06/30/2011
10:18:25
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二元函数的极值不能用两个一元函数的极值拼起来。
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wxcfan123 -
♂
(0 bytes)
()
07/01/2011
08:22:58
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这似乎和我的解法无关
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说了就走 -
♂
(110 bytes)
()
07/03/2011
20:23:56
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初等解法及题目推广.
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jinjing -
(357 bytes)
()
07/01/2011
16:42:27
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有两个大漏洞
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15少 -
♂
(210 bytes)
()
07/02/2011
10:05:31
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A,B,C,D 在4个象限,B>A,您说的,不可能.逻辑佷简易,
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jinjing -
(217 bytes)
()
07/02/2011
14:05:44
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回复:A,B,C,D 在4个象限,B>A,您说的,不可能.逻辑佷简?times;,
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15少 -
♂
(678 bytes)
()
07/03/2011
00:26:38
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补充一下
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15少 -
♂
(133 bytes)
()
07/03/2011
01:47:48
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)设CD 与xy=1 在第一象限的交点为E(E,1/E), 当B>E>A 时, 你的A'BCD 就不再是凸四边形(D点在三角形A
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jinjing -
(0 bytes)
()
07/03/2011
06:19:59
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你的A'BCD 就不再是凸四边形.不是最后的凸四边形,没有关系.
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jinjing -
(117 bytes)
()
07/03/2011
07:20:09
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回复:你的A'BCD 就不再是凸四边形.不是最后的凸四边形,没有关系.
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15少 -
♂
(166 bytes)
()
07/03/2011
07:42:42
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问题在同理上,B,D切线平行,A,C切线平行,只有B=D,A=C,
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jinjing -
(33 bytes)
()
07/03/2011
08:38:39
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你糊涂了吧?
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15少 -
♂
(89 bytes)
()
07/03/2011
08:59:03
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可能有误解,我拿了笔,是不大糊涂大的.
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jinjing -
(0 bytes)
()
07/03/2011
10:04:32
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后面用什么都行
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说了就走 -
♂
(358 bytes)
()
07/03/2011
20:40:08
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对不起,您的"然后就要具体计算切线了,很简单但是没什么意思了。"
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jinjing -
(31 bytes)
()
07/04/2011
06:58:50
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没有关系?你下步的推理如何进行,愿闻其详.
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15少 -
♂
(0 bytes)
()
07/03/2011
09:02:25
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下面是看了不走的答案.
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jinjing -
(148 bytes)
()
07/03/2011
10:02:08
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回复:没有关系?你下步的推理如何进行,愿闻其详.
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jinjing -
(88 bytes)
()
07/03/2011
10:22:17
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English to Chinese
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yma16 -
♂
(215 bytes)
()
05/24/2011
18:11:37
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lifes should be lives
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yma16 -
♂
(0 bytes)
()
05/24/2011
20:44:04
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我们应该安于交换后的生活。
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writeinwater -
(0 bytes)
()
06/06/2011
21:18:55
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随遇而安
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有人夸我是唐僧! -
♂
(0 bytes)
()
06/09/2011
21:54:55
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Re: English to Chinese
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Alshine -
♂
(51 bytes)
()
08/23/2014
06:52:56
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也出一个game
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丹砂 -
♀
(548 bytes)
()
05/24/2011
17:52:08
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Red Grit, let us try your game.
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jinjing -
(108 bytes)
()
05/26/2011
05:36:13
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u r right, but I need a more general strategy...
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丹砂 -
♀
(340 bytes)
()
05/26/2011
13:44:27
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网上犯了逻辑错误,后手策略是随先手变的.....
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jinjing -
(168 bytes)
()
05/26/2011
16:24:08
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不觉得证明有错,因为取了(i,j),和先取(M,N)后取(i,j)结果一样
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丹砂 -
♀
(95 bytes)
()
05/26/2011
18:14:00
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3X4时,先拿右上角那一个,败势
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15少 -
♂
(0 bytes)
()
05/27/2011
02:31:53
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不会吧。。。
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丹砂 -
♀
(106 bytes)
()
05/27/2011
06:24:13
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回复:不会吧。。。
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15少 -
♂
(687 bytes)
()
05/27/2011
07:11:04
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oh, 刚才没想清楚。看来策略跟奇偶有关。。。
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丹砂 -
♀
(0 bytes)
()
05/27/2011
07:37:31
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只拿一个是让先,必输
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15少 -
♂
(0 bytes)
()
05/27/2011
09:17:27
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Your right, I'm too busy to care in the end of semest.er.
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jinjing -
(38 bytes)
()
05/29/2011
09:10:20
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The top right one is a bad move, except for 2x2
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15少 -
♂
(36 bytes)
()
05/27/2011
09:15:53
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2x3呢?再往下推导就是2xn都可以top right one
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丹砂 -
♀
(0 bytes)
()
05/27/2011
09:32:36
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ops, except for 2xN
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15少 -
♂
(0 bytes)
()
05/27/2011
09:37:47
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For any finite matrix, the first player wins
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Pantsonfire -
(371 bytes)
()
05/26/2011
19:02:20
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thx a lot for the info
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丹砂 -
♀
(0 bytes)
()
05/27/2011
06:24:42
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Is that true
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yma16 -
♂
(111 bytes)
()
05/21/2011
22:33:51
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回复:Is that true
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yma16 -
♂
(96 bytes)
()
05/22/2011
05:47:17
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Limit as x goes to what?
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北京大老猫 -
(0 bytes)
()
05/22/2011
12:35:48
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回复:Limit as x goes to a number, such as 0.
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yma16 -
♂
(0 bytes)
()
05/22/2011
22:15:55
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A game
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北京大老猫 -
(699 bytes)
()
05/15/2011
08:38:03
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The first lost.this case is special,most other cases,the first w
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jinjing -
(130 bytes)
()
05/15/2011
09:31:36
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sorry,careless.I woildthink who take the last who win.In your Q,
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jinjing -
(26 bytes)
()
05/15/2011
09:45:08
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回复:A game
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letmeregister -
♂
(419 bytes)
()
05/20/2011
07:28:14
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回复:回复:A game
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jinjing -
(965 bytes)
()
05/20/2011
17:18:18
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This answer can fit any arrangement of this game
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北京大老猫 -
(141 bytes)
()
05/22/2011
12:37:25
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回复:This answer can fit any arrangement of this game
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jinjing -
(140 bytes)
()
05/23/2011
05:50:04
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谢谢掺和~~~
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北京大老猫 -
(0 bytes)
()
05/22/2011
12:38:14
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这类题叫NIM
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丹砂 -
♀
(39 bytes)
()
05/24/2011
17:42:26
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1st loses: 2nd player Keeps odd number of rows and odd numbers o
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修volvo -
♂
(33 bytes)
()
05/24/2011
21:43:59
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回复:1st loses: 2nd player Keeps odd number of rows and odd number
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jinjing -
(117 bytes)
()
05/26/2011
05:55:04
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男人将如何接口呢?
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SoftSpeaker -
♂
(121 bytes)
()
05/12/2011
07:21:11
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麻烦,改日再去看电影吧。
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sediment -
♂
(0 bytes)
()
06/23/2011
15:56:32
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向各位请教:2011的2011次方的第100位是多少?感谢!
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加油!!! -
♂
(0 bytes)
()
05/08/2011
02:38:39
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题目可能是百位数是多少?.....5....=~表百位数相等.
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jinjing -
(118 bytes)
()
05/08/2011
09:15:53
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谢谢回复,可是真的看不懂:(有没有初中生能看得懂的答案?再谢
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加油!!! -
♂
(0 bytes)
()
05/09/2011
00:23:13
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对不起,算错了,答案应该是6,方法对,应是202123611.
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jinjing -
(289 bytes)
()
05/09/2011
04:54:56
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the number is 4, see the result.....
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vw308 -
♂
(7234 bytes)
()
06/09/2011
07:41:11
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如果是百位数,用欧拉定理,phi(1000) = 400, 2011^2011=11^2011=11^11= 611(mod 1
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砂锅2 -
♂
(145 bytes)
()
06/15/2011
19:05:00
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居然给砍掉了: phi(1000) = 400, 2011^2011=11^2011=11^11= 611(mod 1000)
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砂锅2 -
♂
(0 bytes)
()
06/15/2011
19:07:06
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Does 6/2 (1+2) equal 9 or 1?
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哈哈军 -
(0 bytes)
()
05/04/2011
20:27:09
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9
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布衣之才 -
♂
(21 bytes)
()
05/04/2011
20:47:18
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6/(2 (1+2)) equal to 1, 6/2 (1+2) = (6/2) (1+2) = 9
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vw308 -
♂
(0 bytes)
()
06/09/2011
08:20:45
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idiot94哪儿去啦。很可疑!
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贫论员 -
(0 bytes)
()
05/02/2011
07:47:36
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竹说新语 小明的故事
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青青梓竹 -
♀
(843 bytes)
()
04/28/2011
03:14:57