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IBM 11月智力题
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WilliamLuo -
♂
(182 bytes)
()
11/13/2010
16:58:11
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game theory ( 经典例题),和几周前的“必答题”相似,提上来讨论
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guest007 -
♂
(1589 bytes)
()
11/12/2010
13:16:13
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If X has spy 007,100% win. If Y...,60% lost.
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jinjing -
(84 bytes)
()
11/12/2010
15:14:29
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If Y has spy 007, 60% lost. 这个未必吧?
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wushuihe -
♂
(0 bytes)
()
11/15/2010
08:49:39
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严谨得失去幽默,007定义为可左右对手策略的人.
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jinjing -
(0 bytes)
()
11/17/2010
08:23:18
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答案看楼下吧, 很经典的,值得一读, 有人愿意可以帮大家翻译一下
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guest007 -
♂
(0 bytes)
()
11/18/2010
07:51:25
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jinjing's answer,obviously, is incorrect
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guest007 -
♂
(0 bytes)
()
11/15/2010
11:16:33
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哈,我对.
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jinjing -
(0 bytes)
()
11/17/2010
08:26:28
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标准答案 13/15
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guest007 -
♂
(1148 bytes)
()
11/18/2010
07:48:46
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The writer is not qualified being my student.
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jinjing -
(283 bytes)
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11/18/2010
12:40:18
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The answer is right, but y=2/3 is wrong. The trick is that y be
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jinjing -
(58 bytes)
()
11/19/2010
08:28:03
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Quant 面试题:高兴指数(2星)
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康MM -
♀
(196 bytes)
()
11/10/2010
06:22:54
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回复:Quant 面试题:高兴指数(2星)
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wushuihe -
♂
(8 bytes)
()
11/10/2010
08:15:58
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回复:Quant 面试题:高兴指数(2星)
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haha2000 -
♂
(113 bytes)
()
11/10/2010
12:28:29
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回复:回复:Quant 面试题:高兴指数(2星)
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Commentate -
♂
(16 bytes)
()
11/11/2010
08:19:47
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回复:回复:回复:Quant 面试题:高兴指数(2星)
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haha2000 -
♂
(100 bytes)
()
11/12/2010
20:03:25
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If n men and m women how to do?
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jinjing -
(0 bytes)
()
11/11/2010
17:03:23
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回复:If n men and m women how to do?
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wushuihe -
♂
(18 bytes)
()
11/11/2010
17:54:35
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1man,2women,you:2/3,fact:4/3.
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jinjing -
(0 bytes)
()
11/11/2010
21:28:57
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没见过您这么粗心的
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wushuihe -
♂
(0 bytes)
()
11/12/2010
02:09:15
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Thx, You right.
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jinjing -
(0 bytes)
()
11/12/2010
08:45:01
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jinjing 很实在很实在 :)
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guest007 -
♂
(0 bytes)
()
11/12/2010
19:35:53
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请问,为什么 “共有 n*n对男女 n*n*1/n=n” n就是期望值?
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皆兄弟也 -
♂
(0 bytes)
()
11/15/2010
10:56:33
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My answer is ...
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Commentate -
♂
(15 bytes)
()
11/11/2010
09:41:16
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Explanation.....
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Commentate -
♂
(315 bytes)
()
11/11/2010
10:01:53
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回复:Explanation.....
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wushuihe -
♂
(68 bytes)
()
11/11/2010
17:50:48
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how about n=1?....n is right
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jinjing -
(0 bytes)
()
11/11/2010
16:03:20
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Welcome back,
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jinjing -
(347 bytes)
()
11/11/2010
16:59:18
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Correcting: (2n!)!/(n!*n!)types,every type has n!*n! permutation
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jinjing -
(0 bytes)
()
11/11/2010
18:06:09
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(2n!)!/(n!*n!)shoud be (2n)!/(n!*n!)
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jinjing -
(0 bytes)
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11/12/2010
08:47:07