回复：1 - (0.1)^(1/6)

i'm not convinced by this solution.

change the problem to, have a 100% probability of seeing a shooting star in that hour. then...

X=1, for any time interval, 1min, 0.0001sec...

which means, infinite stars will appear? but the initial condition only guarantees a shooting star (or more), which is very possible, but the conclusion that this logic created is not.

 

i think 0.15 is more acceptable

所有跟帖： 

• 回复：回复：1 - (0.1)^(1/6) -calligraphy- ♂ (546 bytes) () 01/30/2011 postreply 07:40:08

• 回复：回复：回复：1 - (0.1)^(1/6) -zeal626- ♂ (345 bytes) () 01/30/2011 postreply 23:36:55

• 回复：回复：回复：回复：1 - (0.1)^(1/6) -calligraphy- ♂ (80 bytes) () 01/31/2011 postreply 06:16:37

• 回复：回复：回复：回复：回复：1 - (0.1)^(1/6) -zeal626- ♂ (593 bytes) () 01/31/2011 postreply 23:55:36

• You are right, they are comman things, 10m included in 1h, -jinjing- ♀ (363 bytes) () 01/30/2011 postreply 20:59:44

• Sorry, I miss ^By *. -jinjing- ♀ (0 bytes) () 01/31/2011 postreply 08:26:11

• 回复：回复：1 - (0.1)^(1/6) -布衣之才- ♂ (195 bytes) () 01/31/2011 postreply 09:56:24