算昏头了还是故意的？你好像忘了一个重要参数。给你机会重新算一下。

"if you shift at 7500 rpm, before the shift:

Engine torque = 140, wheel torque = 4*140 = 560, wheel force = 560 / R." Did you forget about the RPM? I will let you to redo the Math and figure out it yourself.

hint: 560*7500 / R vs. 700*5000 / R, not just 560/R vs 700/R. Maybe this will make you finally understand why your one-gear modeling is flawed as well. And you should also understant the importacne "gearing", which takes advantage of Power, which in turn is the combination of rpm and torque. Not the torque alone.

Actually, in ordr to maintain the maxium acceleration. The shift point should be passed the maximum HP rpm and right before reaching the redline.

所有跟帖： 

• No rpm is involved. -Bonbon330S- ♂ (168 bytes) () 12/08/2005 postreply 16:49:20

• 还记得你小时候学的最简单的弹性碰撞吗？可以帮助你理解为什么算错了 -ifidonlike- ♂ (186 bytes) () 12/08/2005 postreply 17:24:46

• Shall we do a simple units analysis? -Bonbon330S- ♂ (417 bytes) () 12/08/2005 postreply 17:46:34

• 你还不明白，能量守恒！ -ifidonlike- ♂ (320 bytes) () 12/08/2005 postreply 18:13:12

• 你那个方程唯一有效的时候是引擎和车轮都是静止的时候才有效 -Bonbon330S- ♂ (287 bytes) () 12/08/2005 postreply 18:31:19

• 回复：你那个方程唯一有效的时候是引擎和车轮都是静止的时候才有效 -ifidonlike- ♂ (324 bytes) () 12/08/2005 postreply 21:18:51

• 我得承认你的计算方法是对的，但你假设的比例有问题所以导致结论不对 -ifidonlike- ♂ (0 bytes) () 12/08/2005 postreply 21:54:12

• 举例时车轮的rpm（车速）也要考虑 -ifidonlike- ♂ (0 bytes) () 12/08/2005 postreply 22:00:05

• 没有rpm?忘记能量守恒了？ -ifidonlike- ♂ (151 bytes) () 12/08/2005 postreply 17:08:24

• Let me do it in detail for you. -Bonbon330S- ♂ (2319 bytes) () 12/08/2005 postreply 18:10:51