(n^2+1)^2-(n^2+2)*n^2=1,(n^2-1)^2-(n^2-2)*n^2=1.If for any coeff

So,we have solutions: (n^2+1,n) for X^2-(n^2+2)*Y^2=1

                      (n^2-1,n) for X^2-(n^2-2)Y=1

所有跟帖： 

• 回复：(n^2+1)^2-(n^2+2)*n^2=1,(n^2-1)^2-(n^2-2)*n^2=1.If for any co -calligraphy- ♂ (511 bytes) () 01/26/2011 postreply 20:47:19

• Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1, -jinjing- ♀ (344 bytes) () 01/27/2011 postreply 09:35:02

• 回复：Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1, -calligraphy- ♂ (425 bytes) () 01/27/2011 postreply 11:26:44

• 回复：回复：Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1, -jinjing- ♀ (438 bytes) () 01/27/2011 postreply 17:19:24