(n^2+1)^2-(n^2+2)*n^2=1,(n^2-1)^2-(n^2-2)*n^2=1.If for any coeff

来源: 于 2011-01-26 19:08:09 [旧帖] [给我悄悄话] 本文已被阅读：次

So,we have solutions: (n^2+1,n) for X^2-(n^2+2)*Y^2=1

                      (n^2-1,n) for X^2-(n^2-2)Y=1