Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1,

jinjing · 2011-01-27 09:35:02Z

Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1,简介

来源: jinjing 于 2011-01-27 09:35:02 [档案] [旧帖] [给我悄悄话] 阅读数 : (344 bytes)

回答: 回复：(n^2+1)^2-(n^2+2)*n^2=1,(n^2-1)^2-(n^2-2)*n^2=1.If for any co 由 calligraphy 于 2011-01-26 20:47:19

In generail,If we get |9781(M1)^2-(N1)^2|=1,M1 can divided by 2,...continue,at last we get |9781(Mk)^2-(Nk)^2|=1, Mk can't be divided by 2,contradiction,so,.....>1.

I can't copy here and busy,If you want to know more,let me know.I can tell you detail or correct my "blind act" later.

Some answer in web is wrong for P.

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• 回复：Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1, -calligraphy- ♂ (425 bytes) () 01/27/2011 postreply 11:26:44

• 回复：回复：Your Ex,5should be 5^2m,3 ...3^2n...,We get |9781-Z^2|=1, -jinjing- ♀ (438 bytes) () 01/27/2011 postreply 17:19:24

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