thanks. So the general solution should be

wxcfan123 · 2012-05-06 08:28:32Z

thanks. So the general solution should be简介

来源: wxcfan123 于 2012-05-06 08:28:32 [档案] [旧帖] [给我悄悄话] 阅读数 : 0 (416 bytes)

本帖于 2012-06-08 15:15:07 时间, 由版主 idiot94 编辑

回答: 回复：If the total people is 7, what is the number of 3+4 part? Is 由 jinjing 于 2012-05-05 10:04:16

F(N) = SUM_(n1 + n2 + ... nk=N, ni >=3 ) {[C(N, n1)(n1-)!C(N, n2)(n2-1)!...C(N, nk)(nk-1)!)]/D(k)]},

where D(k) is the duplication factor for the decomposition of N = n1 + ... + nk, nj >=3. That is, suppose there are m different numbers in the set {n1, n2, ..., nk}, and they occur in the set l1, l2, ... lm times, (l1 + ... + lm = k), then

D(k) = (l1)!*(l2)!*(l3)!*...(lm)!.

您的位置：文学城 » 论坛 » 脑筋急转 » thanks. So the general solution should be

所有跟帖：

• F(N) = SUM_(n1 + n2 + ... nk=N, ni >=3 ) {[C(N, n1)C(N-n1,n2).. -jinjing- ♀ (66 bytes) () 05/06/2012 postreply 09:37:01

• ... {[C(N, n1)C(N-n1,n2)..C(N-n1-n2-...n(k-1,nk)/D(n1,n2m,,,nk)] -jinjing- ♀ (0 bytes) () 05/06/2012 postreply 09:41:59

请您先登陆，再发跟帖！