... {[C(N, n1)C(N-n1,n2)..C(N-n1-n2-...n(k-1,nk)/D(n1,n2m,,,nk)]

来源: jinjing 于 2012-05-06 09:41:59 [档案] [旧帖] [给我悄悄话] 阅读数 : (0 bytes)

本帖于 2012-06-08 15:15:07 时间, 由版主 idiot94 编辑

回答: F(N) = SUM_(n1 + n2 + ... nk=N, ni >=3 ) {[C(N, n1)C(N-n1,n2).. 由 jinjing 于 2012-05-06 09:37:01

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