F(N) = SUM_(n1 + n2 + ... nk=N, ni >=3 ) {[C(N, n1)C(N-n1,n2)..

来源: jinjing 于 2012-05-06 09:37:01 [] [旧帖] [给我悄悄话] 阅读数 : (66 bytes)
本帖于 2012-06-08 15:15:07 时间, 由版主 idiot94 编辑
回答: thanks. So the general solution should be 由 wxcfan123 于 2012-05-06 08:28:32

I think you are almost right,...,We use D(n1,...nk) better.

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• ... {[C(N, n1)C(N-n1,n2)..C(N-n1-n2-...n(k-1,nk)/D(n1,n2m,,,nk)] -jinjing- ♀ 给 jinjing 发送悄悄话 (0 bytes) () 05/06/2012 postreply 09:41:59

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