看看这个

assume b=a^n

a^a = b^b => a^a = (a^n)^(a^n)

=> a^a = a^(na^n)

=> a = na^n

=> 1 = n a^ (n-1)

=> a = (1/n) ^(1/(n-1))

since n = 1, 2, ..... ,  each n has a pair of a = (1/n)^(1/(n-1)),  b = (1/n)^(n/(n-1))

所有跟帖: 

first two pairs (n starts from 2) -leo爸- 给 leo爸 发送悄悄话 leo爸 的博客首页 (88 bytes) () 11/02/2011 postreply 05:46:41

Leo爸,高,是在是高!您怎么想到assume b=a^n的?I FULE U! 谢谢啦! -thegreatcolour- 给 thegreatcolour 发送悄悄话 (31 bytes) () 11/02/2011 postreply 06:03:31

我一直告诉Leo,做数学要拿出笔和纸 -leo爸- 给 leo爸 发送悄悄话 leo爸 的博客首页 (72 bytes) () 11/02/2011 postreply 06:06:31

文房四宝才用了一半就这么了得。我也曾试到Log,然后, -thegreatcolour- 给 thegreatcolour 发送悄悄话 (265 bytes) () 11/02/2011 postreply 06:18:56

还不够严密 -yddad- 给 yddad 发送悄悄话 (113 bytes) () 11/02/2011 postreply 07:29:49

回复:还不够严密 -yddad- 给 yddad 发送悄悄话 (148 bytes) () 11/02/2011 postreply 08:29:37

对。谢谢你!幸亏闺女没这么反问我。哪位高人能给出证明吗?(NULL) -thegreatcolour- 给 thegreatcolour 发送悄悄话 (0 bytes) () 11/02/2011 postreply 09:41:11

回复:对。谢谢你!幸亏闺女没这么反问我。哪位高人能给出证明吗?(NULL) -yddad- 给 yddad 发送悄悄话 (201 bytes) () 11/02/2011 postreply 10:09:54

初等代数能证明题中的infinite吗?可能还得用下面的BeLe先生的微积分的思路。(NULL) -thegreatcolour- 给 thegreatcolour 发送悄悄话 (0 bytes) () 11/02/2011 postreply 11:05:11

初等代数不用严格的证明 -yddad- 给 yddad 发送悄悄话 (201 bytes) () 11/02/2011 postreply 11:25:35

说只有 n=1 时 a=b, 毫无意义。n 不能是1,因为你不能除零。 -michigan007- 给 michigan007 发送悄悄话 (0 bytes) () 11/02/2011 postreply 12:23:15

leo爸的证明是正确的。您的担心是多余的。 -michigan007- 给 michigan007 发送悄悄话 (1868 bytes) () 11/02/2011 postreply 12:21:06

n 是无限的,不一定由它组成的函数是无限的。 -yddad- 给 yddad 发送悄悄话 (18 bytes) () 11/02/2011 postreply 12:55:15

Again, 您的担心是多余的。 -michigan007- 给 michigan007 发送悄悄话 (1507 bytes) () 11/02/2011 postreply 16:26:11

回复:Again, 您的担心是多余的。 -yddad- 给 yddad 发送悄悄话 (193 bytes) () 11/02/2011 postreply 18:29:02

You were confused -michigan007- 给 michigan007 发送悄悄话 (676 bytes) () 11/03/2011 postreply 06:25:20

我没有说他是是错的只是说不严密 -yddad- 给 yddad 发送悄悄话 (445 bytes) () 11/02/2011 postreply 13:27:21

Where is your logic? -michigan007- 给 michigan007 发送悄悄话 (4941 bytes) () 11/02/2011 postreply 16:28:30

we are using different logic. -yddad- 给 yddad 发送悄悄话 (4905 bytes) () 11/02/2011 postreply 18:50:02

Your logic is wrong. -michigan007- 给 michigan007 发送悄悄话 (2647 bytes) () 11/03/2011 postreply 09:53:05

Please read the question carefully -michigan007- 给 michigan007 发送悄悄话 (1376 bytes) () 11/02/2011 postreply 16:48:29

Yes, I do read carefully. -yddad- 给 yddad 发送悄悄话 (420 bytes) () 11/02/2011 postreply 18:23:58

You were confused again -michigan007- 给 michigan007 发送悄悄话 (2074 bytes) () 11/03/2011 postreply 06:23:18

哈哈 -yddad- 给 yddad 发送悄悄话 (101 bytes) () 11/03/2011 postreply 07:01:24

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