leo爸的证明是正确的。您的担心是多余的。

回答: 还不够严密yddad2011-11-02 07:29:49

很明显, n = 2,3, ..... , for each na = (1/n)^(1/(n-1))  b = (1/n)^(n/(n-1))  是不同的。由于 n 可取无限位数 23,… ,无须证明infinite。请注意, n 不能是1,因为你不能除零。

所有跟帖: 

n 是无限的,不一定由它组成的函数是无限的。 -yddad- 给 yddad 发送悄悄话 (18 bytes) () 11/02/2011 postreply 12:55:15

Again, 您的担心是多余的。 -michigan007- 给 michigan007 发送悄悄话 (1507 bytes) () 11/02/2011 postreply 16:26:11

回复:Again, 您的担心是多余的。 -yddad- 给 yddad 发送悄悄话 (193 bytes) () 11/02/2011 postreply 18:29:02

You were confused -michigan007- 给 michigan007 发送悄悄话 (676 bytes) () 11/03/2011 postreply 06:25:20

我没有说他是是错的只是说不严密 -yddad- 给 yddad 发送悄悄话 (445 bytes) () 11/02/2011 postreply 13:27:21

Where is your logic? -michigan007- 给 michigan007 发送悄悄话 (4941 bytes) () 11/02/2011 postreply 16:28:30

we are using different logic. -yddad- 给 yddad 发送悄悄话 (4905 bytes) () 11/02/2011 postreply 18:50:02

Your logic is wrong. -michigan007- 给 michigan007 发送悄悄话 (2647 bytes) () 11/03/2011 postreply 09:53:05

Please read the question carefully -michigan007- 给 michigan007 发送悄悄话 (1376 bytes) () 11/02/2011 postreply 16:48:29

Yes, I do read carefully. -yddad- 给 yddad 发送悄悄话 (420 bytes) () 11/02/2011 postreply 18:23:58

You were confused again -michigan007- 给 michigan007 发送悄悄话 (2074 bytes) () 11/03/2011 postreply 06:23:18

哈哈 -yddad- 给 yddad 发送悄悄话 (101 bytes) () 11/03/2011 postreply 07:01:24

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