不失一般性,1箱有钱,用一表选一箱.二.....不换有3情况,一23,1二3,12三.选中为1/3...
换有6......,一23_______1二3,12三
1二3________一23,12三
12三_______一32 1二3
选中为 2/6=1/3. 换不换一样.
不失一般性,1箱有钱,用一表选一箱.二.....不换有3情况,一23,1二3,12三.选中为1/3...
换有6......,一23_______1二3,12三
1二3________一23,12三
12三_______一32 1二3
选中为 2/6=1/3. 换不换一样.
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谢谢,这个回答很有说服力!受教了.
-xyz100-
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08/10/2012 postreply
10:04:43
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你这个例子没考虑主持人开箱的情况。
-bpyrmjpmrl-
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08/10/2012 postreply
17:29:41
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模型应这样做:
-wxcfan123-
♂
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08/11/2012 postreply
14:40:18
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