One more mistakes.

来源: wxcfan123 于 2011-08-06 09:57:31 [] [旧帖] [给我悄悄话] 本文已被阅读： 0 次 (82 bytes)
回答: I do the rest for my too much mistakes. 由 jinjing 于 2011-08-05 19:38:14

-f(1+0)+f(f(1))<=-[0*f(1)+f(f(1))]+f(f(1)). It is minus at the begining.

所有跟帖： 

• Thx,...you said these Qs are too tough at beginning,...you under -jinjing- ♀ 给 jinjing 发送悄悄话 (19 bytes) () 08/06/2011 postreply 10:36:09

• I'm right, you want to make a joke, I know. -jinjing- ♀ 给 jinjing 发送悄悄话 (0 bytes) () 08/06/2011 postreply 11:04:53

• In case you did not get it. -wxcfan123- ♂ 给 wxcfan123 发送悄悄话 (82 bytes) () 08/06/2011 postreply 12:57:56

• Thx.Yes, you are right. It is easy for me,though I made mistakes -jinjing- ♀ 给 jinjing 发送悄悄话 (0 bytes) () 08/08/2011 postreply 16:27:42

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