In case you did not get it.

来源: wxcfan123 于 2011-08-06 12:57:56 [] [旧帖] [给我悄悄话] 本文已被阅读： 次 (82 bytes)
回答: I'm right, you want to make a joke, I know. 由 jinjing 于 2011-08-06 11:04:53

f(1+0)<=0*f(1)+f(f(1))

-f(1+0)>=-[0*f(1)+f(f(1))] (not <=)

所有跟帖： 

• Thx.Yes, you are right. It is easy for me,though I made mistakes -jinjing- ♀ 给 jinjing 发送悄悄话 (0 bytes) () 08/08/2011 postreply 16:27:42

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