P(abCdef,abcDef,abcdEf,abcdeF,abcdef}=.681^2.319+.681^3.319+..

来源: jinjing 于 2011-02-06 17:43:32 [档案] [旧帖] [给我悄悄话] 阅读数 : 0 (219 bytes)

回答: why P(abCdef,abcDef,abcdEf,abcdef}=.535? 由 wushuihe 于 2011-02-06 12:31:45

Sorry,I'm outside, a litttle carelessness.Thank you remind me,It should be:

P(notA)=P(notB)=...P(notF)=0.681.P(A)=P(B)=...=.319

So,P(notA*notB)=P(notA)*P(notB),they are independent.

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