回复：P(abCdef,..,f}=.681^2.319+.681^3.319+..=.464=.681*.681

来源: jinjing 于 2011-02-06 17:47:52 [档案] [旧帖] [给我悄悄话] 阅读数 : (0 bytes)

回答: P(abCdef,abcDef,abcdEf,abcdeF,abcdef}=.681^2*.319+.681^3*.319+.. 由 jinjing 于 2011-02-06 17:43:32

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