试解

来源: monseigneur 2024-02-29 23:13:08 [] [旧帖] [给我悄悄话] 本文已被阅读: 次 (706 bytes)

Suppose the top point isn't a qualified point. Otherwise the problem is already solved. That is, its three edges a,b,c cannot form a triangle. Assume a is larger than b and c. Then a > b+c > y

Meanwhile:  x+ b > a,     z+c >a,      so x+z+b+c> 2a
Remember a > b+c,  so x+z > a      (Eq1)

Remember a > y, so a+z>y+z > x     (Eq2)

Similarly, a+x > y+ x > z        (Eq3)

Combine Eq 123, it turns out a, x, z can form a triangle. 

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