如图,截取BE=BA,角BAE=角BEA=72度,又角ADE=72度,所以AE=AD,即角AED=72度,EC=DC-DE=BE-DE=BD=AD=AE, 所以AEC是等腰三角形,角ACB=72/2=36, 所以AB=AC

如图,截取BE=BA,角BAE=角BEA=72度,又角ADE=72度,所以AE=AD,即角AED=72度,EC=DC-DE=BE-DE=BD=AD=AE, 所以AEC是等腰三角形,角ACB=72/2=36, 所以AB=AC

•
高。我又是用三角解的。
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12/10/2023 postreply
14:27:36
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