感觉可以凑成(x^2+a)^2-(x+b)^2, 然后用平方差公式进行因式分解,解得待定系数a=1/2, b=-7/2, 代入后,因式分解为 (x^2+x-3)(x^2-x+4), 可解得两实数根和两虚数根
感觉可以凑成(x^2+a)^2-(x+b)^2, 然后用平方差公式进行因式分解,解得待定系数a=1/2, b=-7/2, 代入后,因式分解为 (x^2+x-3)(x^2-x+4), 可解得两实数根和两虚数根
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