(x-2/3*3^0.5)^2+(y-2/3*3^0.5)^2+(z-2/3*3^0.5)^2=1,
x^2+y^2+(z-2)^2=1
(x-2/3*3^0.5)^2+(y-2/3*3^0.5)^2+(z-2/3*3^0.5)^2=1,
x^2+y^2+(z-2)^2=1
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两球心之间的距离是2sqrt(2) > 两球半径的和2,所以不相交
-万斤油-
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07/27/2023 postreply
06:46:21
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对不起,我改了一下。你看看。谢谢。
-yma16-
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07/27/2023 postreply
08:03:16
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我有一个一般的问题。
-yma16-
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07/27/2023 postreply
08:16:50
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并非消去一元后得到的方程就是解,就像x+y=1, x-y=1, 消去y后得x=1, 并非意味着解是一条直线
-万斤油-
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07/27/2023 postreply
10:37:44
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