IF E(1)=1, then E(n+1)=E(n)+1/(2n+1), So E(100)=1/199+1/197+1/19

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• E(100)=1/199+1/197+1/197+.....+1/3+1=3.27869.... -jinjing- ♀ (0 bytes) () 08/10/2012 postreply 14:15:05

• 谢谢！忘了说请教啦！我再想想 E(n+1)=E(n)+1/(2n+1) -绿袖儿- ♀ (0 bytes) () 08/10/2012 postreply 15:32:18

• 谢题！We can get it when n=1,2,3 .if you are not mathematician. -jinjing- ♀ (0 bytes) () 08/10/2012 postreply 16:05:58