回复：Yes, I think C(6,3)*2*2+6!/6=200..

I am a slow guy, let's slow down a bit,

 

Two parts: 123   456

           132   456

           123   465

           132   465

How about we first select 456 which is counted as new one in C(6,3)? We would have

           456 123

           456 132

           465 123

           465 132

doubly counted in your original calculation.

Does my thinking make sense?

 

所有跟帖： 

• 回复：回复：Yes, I think C(6,3)*2*2+6!/6=200.. -jinjing- ♀ (360 bytes) () 05/04/2012 postreply 08:56:10

• Still not convinced -Slowguy- ♂ (162 bytes) () 05/04/2012 postreply 09:06:41

• You are right, should be C(6,3)/2*2*2 + 6!/6=160. two parts 10 c -jinjing- ♀ (96 bytes) () 05/04/2012 postreply 10:35:30

• Thanks -Slowguy- ♂ (0 bytes) () 05/04/2012 postreply 10:50:22