[C(20,6)C(18,4)+...+C(20,9)C(18,1)+C(20,10)]/C(38,10)

来源: jinjing 于 2011-10-21 09:07:14 [档案] [旧帖] [给我悄悄话] 阅读数 : (0 bytes)

回答: [C(20,6)C(18,4)+C(20,7)C(18,3)+...+C(20,9)C(18,1)+C(20,10)]/C(38 由 jinjing 于 2011-10-21 09:05:05

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