回复:My proof.

回答: My proof.jinjing2011-08-11 07:25:46

This is your construction - get 14A and 14B ... and you can not get it.

It does not prove it can not be construcated by other ways.

Suggestion:

Read 康MMprevious post and follows.康M guess, this construction of 7 is unique. Try to add one point on it, to see what happen, then you got some feeling of case 8. But, you can not prove this construction is unique. Key point: all points are on two unit circle A and D, that is generic.

所有跟帖: 

Your proof is wrong in logic. -jinjing- 给 jinjing 发送悄悄话 (0 bytes) () 08/11/2011 postreply 11:59:32

From E.LTrils, plus one point at most incrse 2A, 1B, later 2A,2B -jinjing- 给 jinjing 发送悄悄话 (294 bytes) () 08/11/2011 postreply 15:20:59

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