f(0)=-128/9, as you did. It is my carelessness....
I think pfollowing is the explanation: a(x-5)^2+b,...a=-b/9...
ff=-b/9(-b/9(x-5)^2+b-5)^2+b=0,only b=2,x=5 is unique real root, b=8,has three 3 roots,not good.key point b-5 <0. Here is not riddle.
f(0)=-128/9, as you did. It is my carelessness....
I think pfollowing is the explanation: a(x-5)^2+b,...a=-b/9...
ff=-b/9(-b/9(x-5)^2+b-5)^2+b=0,only b=2,x=5 is unique real root, b=8,has three 3 roots,not good.key point b-5 <0. Here is not riddle.
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Why make stupid calcul when
-15少-
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07/15/2011 postreply
17:33:47
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You totally misunderstanding me, f(x)=a(X-5)^2+b,why b=2? you te
-jinjing-
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07/15/2011 postreply
18:04:50
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you tell me,please,not 8.
-jinjing-
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07/15/2011 postreply
18:07:08
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Ms. Kang has explained, her explanation is not as clear as you d
-15少-
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07/16/2011 postreply
06:30:03
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Why f(8)=0?Cs we use a Thm, It is unknow for most people here.
-jinjing-
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07/16/2011 postreply
08:19:30
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You like calcul
-15少-
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07/16/2011 postreply
09:10:20
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回复:You totally misunderstanding me, f(x)=a(X-5)^2+b,why b=2? you
-15少-
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07/16/2011 postreply
06:09:01
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