大约可以这么想
任意 质数 p
任意其2个整数 a and b, Prob( p | gcd(a, b)) is about 1/p^2
从这里接着算, 就可以了.
大约可以这么想
任意 质数 p
任意其2个整数 a and b, Prob( p | gcd(a, b)) is about 1/p^2
从这里接着算, 就可以了.
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