no

来源: guest007 于 2010-05-15 21:58:07 [] [旧帖] [给我悄悄话] 阅读数 : (524 bytes)
回答: 新题 由 guest007 于 2010-05-14 08:02:07

your answer is no better than this early one -
"此时，鸭子距岸3r/4。然后，鸭子沿直径向岸游3r/4=0.75r，同时狐狸须跑半个半径为r的圆弧，即3.14r，抓鸭子。3.14r/0.75r > 4.鸭子先到岸而起飞。 "...

See optimal route and solution see 皆兄弟's answer 10-05-12 18:59:12 he is incorrec just because he though fox was not smart.

this is a old and 经典追逐，numbers in my question is duck's minimum velocity (0.21723363 to fox) - all other numbers (1/4 1/ PI+1...) is not right for obvious reasons.


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