I mean vf is larger than that, the duck still can free

来源: guest007 于 2010-05-14 14:23:47 [] [旧帖] [给我悄悄话] 阅读数 : (497 bytes)
回答: 鸭子被吃掉了 由 guest007 于 2010-05-14 09:26:39

The question expects to see that when even V (fox) or V (cat) is at 4.60338811 times of V (duck), the duck can still free...

Cat or Fox at this speed (4.60338811 times of duck which is > 4.1415926 times), your answer is not related at all.

You have already figured out the right path before, maybe i jinjing-ed you...

answer is 鸭在半径为x 的圆上与狐周旋于同一直径远端，然后沿切线游完。 I belive you understand now.

Now i hope jinjing can understand as well - hehe

所有跟帖： 

• 鸭在半径为x 的圆上与狐周旋于同一直径远端，不可能. -jinjing- ♀ 给 jinjing 发送悄悄话 (170 bytes) () 05/14/2010 postreply 15:52:06

• 回复：鸭在半径为x 的圆上与狐周旋于同一直径远端，不可能. -guest007- ♀ 给 guest007 发送悄悄话 (64 bytes) () 05/15/2010 postreply 21:26:51

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