仔细再想,偶数也可二次完成。
1. at A city, 配 (n-2)/2 对,余二根孤线。
2. at B city, 找出对子和二根孤线。
3. at B city, 连接对子和一根孤线成一长线,(见上贴), 余一根孤线。
4. at A city, 先找出那一根孤线,然后再解(见上贴)。
春节快乐!!
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哦, you have already done that.
-guest007-
♀
(19 bytes)
()
02/14/2010 postreply
13:07:28
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回复:哦, you have already done that.
-cowgg-
♂
(479 bytes)
()
02/18/2010 postreply
17:34:29