Reply to Jinjing on question 3

This is your equation. P(a^bd^cd)=.35*.3+.65*(.3/(1-.35))=.405

The first part is correct. But the second part is not. There are two ways that c could be the first one dead. One way is for A to kill C. In that case, B gets to shoot next. The other way is for A to miss and then B kills C. In that case, A gets to shoot next. The prob is different depending on who shoots first, right? So your equation should be changed to this:

P(a^bd^cd)=.35*.3+(.3*.5+.7*.5)*(.3/(1-.35))=.336

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回复:Reply to Jinjing on question 3 -guest007- 给 guest007 发送悄悄话 (32 bytes) () 01/29/2010 postreply 21:27:36

回复:回复:Reply to Jinjing on question 3 -endofsuburbia- 给 endofsuburbia 发送悄悄话 endofsuburbia 的博客首页 (35 bytes) () 01/29/2010 postreply 21:49:39

回复:回复:回复:Reply to Jinjing on question 3 -guest007- 给 guest007 发送悄悄话 (93 bytes) () 01/30/2010 postreply 21:22:57

回复:回复:回复:回复:Reply to Jinjing on question 3 -endofsuburbia- 给 endofsuburbia 发送悄悄话 endofsuburbia 的博客首页 (32 bytes) () 01/30/2010 postreply 22:15:37

回复:Reply to Jinjing on question 3 -jinjing- 给 jinjing 发送悄悄话 (62 bytes) () 01/29/2010 postreply 21:56:48

Ha, I'm right,,you are... -jinjing- 给 jinjing 发送悄悄话 (16 bytes) () 01/29/2010 postreply 23:04:31

.336 is correct -dynamic- 给 dynamic 发送悄悄话 (0 bytes) () 01/30/2010 postreply 00:09:55

回复:Wrong:P(a^bd^cd)=.336 -Jinjing- 给 Jinjing 发送悄悄话 (141 bytes) () 01/30/2010 postreply 07:51:42

回复You're right,I'm going down. -Jinjing- 给 Jinjing 发送悄悄话 (85 bytes) () 01/30/2010 postreply 09:54:42

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