Let me define losing hand as whenever you create this hand to your opponent, you win.
1. 任何时候,不能留给对手有两堆数目相等的情况。
That’s right-
I will summarize your conclusion one step further – 0-X-X is a losing hand.
2. 如果有一堆变成1的时候,留给对手让两堆数目相差是1.
That’s incorrect(practically correct though). 1-X-(X+1) is NOT necessarily a losing hand. For example 1-3-4. You are just one step close to the common solution.
3. 如果任何一堆是2的时候。保持另两堆的数目相差等于2.
That’s incorrect (practically correct though). 2-X-X+2 is NOT necessary a losing hand. For example 2-6-8. You are just one step close to the common solution.
4. 任何一堆都大于2的时候,保持另两堆的数目相差大于2.
That’s incorrect for obvious reasons (3-4-7; 3-5-6). It might be more difficult than you think.