根据以上分析,要在刚超过1/2的时候停止,只能是在奇数次停止,而且最后一次是正面,前面正反相等。
1/2 + 2/3 * C_2^1 (1/2)^3 + 3/5 C_4^2 (1/2)^5 + ....
= \sum_{n=0}^\infty (n+1)/(2n+1) C_{2n}^n (1/2)^(2n+1)
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