thanks a lot, I also find a different approach using function pe

来源: cloudate 于 2009-08-21 00:21:06 [] [博客] [旧帖] [给我悄悄话] 阅读数 : (0 bytes)

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• thanks I also find a different approach using percentrank() -cloudate- ♂ 给 cloudate 发送悄悄话 cloudate 的博客首页 (0 bytes) () 08/21/2009 postreply 00:21:55

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