第二题太简单,不能作为竞赛题。延长QP致外接圆于Q'和P',
由条件可得MKL与AQP相似。得BQ*AQ=AP*PC,又知:QQ'*(QP+PP')=PP'(QP+QQ')得QQ'=PP',由此可知,MQ'=MP',所以M是P'Q'的中点,OM也垂直平分PQ,所以OM=OP,得证.10分钟不到,搞定.
problem 2 is too easy
本帖于 2009-07-28 16:38:03 时间, 由普通用户 康MM 编辑
第二题太简单,不能作为竞赛题。延长QP致外接圆于Q'和P',
由条件可得MKL与AQP相似。得BQ*AQ=AP*PC,又知:QQ'*(QP+PP')=PP'(QP+QQ')得QQ'=PP',由此可知,MQ'=MP',所以M是P'Q'的中点,OM也垂直平分PQ,所以OM=OP,得证.10分钟不到,搞定.
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