回复：可能是这样

A(0)---a------b-----c----d----e-----B(1000)

I guess

1. take 4 and 5 to b
2. meet 2 at a and pick 3 at when meet him
3. chnage 3 and 4 when meet 4 at c (i.e take 4 leave 3)
4. leave 4 at e
5. go back to meet 3 at d
then all arrive B at same time.

所有跟帖： 

• adamsmth's solution, 167.5 sec, is better than mine, 170.6 sec. -morefun- ♂ (0 bytes) () 09/24/2008 postreply 09:15:04

• “生肖迷宫”的题不会如此容易，再多考虑考虑吧 -孤苦的人- ♂ (129 bytes) () 09/24/2008 postreply 10:47:59

• 原来是生肖的马甲。 -火球魔法- ♂ (12 bytes) () 09/24/2008 postreply 21:09:01