The driver first takes 2 persons to y and go back to meet other 2 person at x, and then all person arive B at same time.
we have 2 equastions:
y/10 +1000-y = y/10+(y-x)/10+(1000-x)/10
x+(1000-x)/10 = y/10+(y-x)/10+(1000-x)/10
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x=154, y=846
-adamsmth-
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09/23/2008 postreply
10:45:19
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别忘了车往回开时也要时间的,(x+y cant be 1000)
-xyz100-
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10/22/2008 postreply
14:00:56