
Draw a perpendicular line, a being the upper section, b the lower section. It also divides the 19 triangle into two areas, x and y.
(a/b)^2=x/8=y/12=(x+y)/(8+12)=19/20
let rectangle area be S.
19*2/S=a/b=sqrt(19/20)
S=4*sqrt(95)

Draw a perpendicular line, a being the upper section, b the lower section. It also divides the 19 triangle into two areas, x and y.
(a/b)^2=x/8=y/12=(x+y)/(8+12)=19/20
let rectangle area be S.
19*2/S=a/b=sqrt(19/20)
S=4*sqrt(95)
•
这个思路跟我的差不多
-贫论贫论-
♂
(0 bytes)
()
03/18/2026 postreply
05:06:21
WENXUECITY.COM does not represent or guarantee the truthfulness, accuracy, or reliability of any of communications posted by other users.
Copyright ©1998-2026 wenxuecity.com All rights reserved. Privacy Statement & Terms of Use & User Privacy Protection Policy