都是先拿胜,凑5法.

1)取2,必得到7,12,17,22,27

2)取1,6,16,21,26.

3)4)取1,最后6子,对方先取,先者可控奇,偶.

所有跟帖： 

• don't understand your 3/4, normally people do working backwords, -calligraphy- ♂ (125 bytes) () 02/14/2012 postreply 12:24:58

• Pease see my proof.....If we changed Q,1to m 27 to n,...can get -jinjing- ♀ (238 bytes) () 02/14/2012 postreply 19:37:21

• Correction: s even,S odd. -jinjing- ♀ (0 bytes) () 02/14/2012 postreply 21:04:44

• in both cases, the first taker can win. see his last slide. -calligraphy- ♂ (0 bytes) () 02/15/2012 postreply 06:51:31

• Not right . -jinjing- ♀ (0 bytes) () 02/27/2012 postreply 06:26:25

• 第3题，先拿赢 -花心鬼- ♂ (648 bytes) () 02/15/2012 postreply 11:57:02

• 很好，换种说法会更准确“如果对手拿奇数（1，3），拿适当数目，换坑！”hard for kids. -calligraphy- ♂ (0 bytes) () 02/15/2012 postreply 14:16:13