Roughly, S(n+1) < 2nS(n) < 2(n+1)S(n) ~ 2(n+1)!. Should be conve
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• Sorry, you lost 2^n......S(n+1) < 2nS(n) < ...2^n(n!)S(1) -jinjing- ♀ (0 bytes) () 10/10/2011 postreply 20:23:12
• Sorry, you lost 2^n......S(n+1) < 2nS(n) < ...2^n(n!)S(1) -jinjing- ♀ (0 bytes) () 10/10/2011 postreply 20:23:12