f(1+0)<=0*f(1)+f(f(1))
-f(1+0)>=-[0*f(1)+f(f(1))] (not <=)
• Thx.Yes, you are right. It is easy for me,though I made mistakes -jinjing- ♀ (0 bytes) () 08/08/2011 postreply 16:27:42