回复:有没有好办法?

来源: 15少 2011-04-29 16:20:14 [] [博客] [旧帖] [给我悄悄话] 本文已被阅读: 0 次 (36462 bytes)
回答: 有没有好办法?cma2011-04-22 20:02:58

The third side c is odd, let c=2x-1,


c>3, c<133, so 2<x<67


s=(2x-1+68+65)/2=x+66


 


S²=(x-2)*(x+1)*(67-x)*(66+x)


 









































Possible Commun


Divisor



x-2



x+1



67-x



66+x



x-2



 



3



5, 13



2, 17



x+1



 



 



2, 17



5, 13



67-x



 



 



 



7,19



66+x



 



 



 



 



 


1) x-2=3n


s=66+x = 68+3n , s cannot be divided by 3.


s cannot divided neither by 2 nor by 13*. all possible factors of s are 19, 17, 7, 5


a.       s=19m (3<m<7), so m=5


m=5, x=29, x-2=27, x+1=30, 67-x=38, 66+x=95


c=57, S²=(3*9)*(3*2*5)*(2*19)*(19*5), S=3*3*2*5*19


b.      s=17m  (4<m<8),  m=5, 7


m=5, x=9, x+1=10=5*2


m=7, x=53, x-2=51=3*17, x+1=54, 67-x=14, 66+x=119


c=105, S²=(3*17)*(3*2*9)*(2*7)*(17*7), S=3*2*3*7*17


c.       s=7m (9<m<19), m=17, idem b


d.      s=5m (13<m<27), m=19 idem a.


 


2) x-2 =3n+1,


66+x = 3* (23+n) è 66+x= 9m (7<m<14), m=8,9,10,13


m=8, x=6, 67-x=61


m = 9, x=15, x-2=13, x+1=16, 67-x=52, 66+x=81


c=29,  S²=(13)*(4*4)*(2*2*13)*(9*9), S=13*4*2*9


m=10, x=24, 67-x=43


m=13, x=51, x-2=49, x+1=52, 67-x=16, 66+x=117


c=101, S²=(7*7)*(2*2*13)*(4*4)*(13*9), S=7*2*13*4*3


 


3) x-2 =3n+2


67-x = 3*(21-n) à 67-x = 9m (1<m<8), so = 1, 2, 4, 5, 7


m=1, x=58, x+1=59


m=2, x=49, x-2=47


m=4, x=31, x-2=29


m=5, x=22, x+1=23


m=7, x=4, x-2=2, x+1=5, 67-x=63, 66+x=70


c=7, S²=(2)*(5)*(7*9)*(7*2*5), S=2*5*7*3 = 210


 


************************************


x cannot be divided by 2 neither


if x is even, then n is also even , n=2m,


         then x-2=3*2m, x+1=3(2m+1)


         m=3p


                  x-2= 2*9p, x+1= 2*9p+3,


                  p must be divided by 3, so p= 3, x=56,


                  67-x = 11


          m=3p+1,


                  x+1=6m+3=18p+9=9(2p+1), x-2=6(3p+1)


                  2p + 1 must be divided by 3, so p=1, x=26,


                  x+66=92=4*23


           m=3p +2 


                  x-2=9p+6, x+1= 9p+9 = 9(p+1)


                  p+1 must be divided by 3, so p=2, x=26,


                  67-x=41


 


s cannot be divided by 13, otherwise x+1 can also be divided by 13 (see table)


x+1=13m,


x-2=3n =13m-3, m can not be odd, otherwise x-2 and x are both even number.


The smallest m is 6 which gives x=77, too big.

请您先登陆,再发跟帖!

发现Adblock插件

如要继续浏览
请支持本站 请务必在本站关闭/移除任何Adblock

关闭Adblock后 请点击

请参考如何关闭Adblock/Adblock plus

安装Adblock plus用户请点击浏览器图标
选择“Disable on www.wenxuecity.com”

安装Adblock用户请点击图标
选择“don't run on pages on this domain”