The third side c is odd, let c=2x-1,
c>3, c<133, so 2<x<67
s=(2x-1+68+65)/2=x+66
S²=(x-2)*(x+1)*(67-x)*(66+x)
Possible Commun Divisor | x-2 | x+1 | 67-x | 66+x |
x-2 | 3 | 5, 13 | 2, 17 | |
x+1 | 2, 17 | 5, 13 | ||
67-x | 7,19 | |||
66+x |
1) x-2=3n
s=66+x = 68+3n , s cannot be divided by 3.
s cannot divided neither by 2 nor by 13*. all possible factors of s are 19, 17, 7, 5
a. s=19m (3<m<7), so m=5
m=5, x=29, x-2=27, x+1=30, 67-x=38, 66+x=95
c=57, S²=(3*9)*(3*2*5)*(2*19)*(19*5), S=3*3*2*5*19
b. s=17m (4<m<8), m=5, 7
m=5, x=9, x+1=10=5*2
m=7, x=53, x-2=51=3*17, x+1=54, 67-x=14, 66+x=119
c=105, S²=(3*17)*(3*2*9)*(2*7)*(17*7), S=3*2*3*7*17
c. s=7m (9<m<19), m=17, idem b
d. s=5m (13<m<27), m=19 idem a.
2) x-2 =3n+1,
66+x = 3* (23+n) è 66+x= 9m (7<m<14), m=8,9,10,13
m=8, x=6, 67-x=61
m = 9, x=15, x-2=13, x+1=16, 67-x=52, 66+x=81
c=29, S²=(13)*(4*4)*(2*2*13)*(9*9), S=13*4*2*9
m=10, x=24, 67-x=43
m=13, x=51, x-2=49, x+1=52, 67-x=16, 66+x=117
c=101, S²=(7*7)*(2*2*13)*(4*4)*(13*9), S=7*2*13*4*3
3) x-2 =3n+2
67-x = 3*(21-n) à 67-x = 9m (1<m<8), so = 1, 2, 4, 5, 7
m=1, x=58, x+1=59
m=2, x=49, x-2=47
m=4, x=31, x-2=29
m=5, x=22, x+1=23
m=7, x=4, x-2=2, x+1=5, 67-x=63, 66+x=70
c=7, S²=(2)*(5)*(7*9)*(7*2*5), S=2*5*7*3 = 210
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x cannot be divided by 2 neither
if x is even, then n is also even , n=2m,
then x-2=3*2m, x+1=3(2m+1)
m=3p
x-2= 2*9p, x+1= 2*9p+3,
p must be divided by 3, so p= 3, x=56,
67-x = 11
m=3p+1,
x+1=6m+3=18p+9=9(2p+1), x-2=6(3p+1)
2p + 1 must be divided by 3, so p=1, x=26,
x+66=92=4*23
m=3p +2
x-2=9p+6, x+1= 9p+9 = 9(p+1)
p+1 must be divided by 3, so p=2, x=26,
67-x=41
s cannot be divided by 13, otherwise x+1 can also be divided by 13 (see table)
x+1=13m,
x-2=3n =13m-
The smallest m is 6 which gives x=77, too big.