It is not true if you try 3>2>1 since 8<9. How can you add some conditions to make if x>y>1 then y^x>x^y true?
if x>y>1 then y^x>x^y?
I read a post saying if x>y>1 then y^x>x^y.
It is not true if you try 3>2>1 since 8<9. How can you add some conditions to make if x>y>1 then y^x>x^y true?
It is not true if you try 3>2>1 since 8<9. How can you add some conditions to make if x>y>1 then y^x>x^y true?
所有跟帖:
• a sufficient condition is x>y>e -dynamic- ♂ (206 bytes) () 03/31/2008 postreply 02:15:16