say a
1) if a>=3, then b>=a+2, c>=a+4
then, a*a+11 - b*c = a*a+11-a*a-8*a-8=3-8*a<0
contradiction!
so a=2
2) since a*a+11=15 >=b*c, the only answer is
b=3, c=5
1) if a>=3, then b>=a+2, c>=a+4
then, a*a+11 - b*c = a*a+11-a*a-8*a-8=3-8*a<0
contradiction!
so a=2
2) since a*a+11=15 >=b*c, the only answer is
b=3, c=5