回复：回复：A General Solution

I get k=11(2t-1).Math is wonderful.At first I want deny this question.You see the anwser is infinite.I think the key point is the prime factors.The 100000.....1=p1^(2m1-1)*p2(2m2-1)...pf^(2mf-1)*q1^1(2n1)*q2(2n2)...*q(2ng),if max{(2m1-1),(2m2-1),...(2mf-1),2n1,2n2,...2ng}=1,no solution.Otherwise,any x=p1^2s1*p2^2s2...p^2sf*Q1^2c1*q2^2c2...qg^2c*r1^2j1*...re^2jr
is anwser,sytisfy contitions:si>=mi and square root of x is <1000......1.I think this anwser is too general to be intresting.