Here you confused “given an n, a = (1/n)^(1/(n-1)) and b = (1/n)^(n/(n-1)) are uniquely determined” with aa or bb are uniquely determined again.
通过取一阶导数很容易证明单调递增与单调递减。
Here you confused “given an n, a = (1/n)^(1/(n-1)) and b = (1/n)^(n/(n-1)) are uniquely determined” with aa or bb are uniquely determined again.
通过取一阶导数很容易证明单调递增与单调递减。