P(c) = 0 (given)
c(c-a)(c-b) = 13
13 is a prime number, c has to be 1
since 0<a<b, a = 2, b = 14, c = 1 is the only solution
P(c) = 0 (given)
c(c-a)(c-b) = 13
13 is a prime number, c has to be 1
since 0<a<b, a = 2, b = 14, c = 1 is the only solution
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啥时给的P(c)=0啊?
-教导l-
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10/24/2016 postreply
14:34:40
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P(x) is divisible by x-c
-skyport-
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10/24/2016 postreply
14:35:11
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哇,这个居然没想到。
-教导l-
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10/24/2016 postreply
14:37:10
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还是大师兄牛LOL
-一九得九-
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10/24/2016 postreply
14:45:15
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c=1, c-a=-1, c-b=-13
-小睿儿-
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10/24/2016 postreply
14:34:50
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做对了,俺 忘记了可以是负数 :)
-skyport-
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10/24/2016 postreply
14:36:17
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agree with you
-rcyanking-
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10/24/2016 postreply
14:36:28
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小睿太聪明了,我到现在才明白你上面的回帖。佩服
-一九得九-
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10/24/2016 postreply
14:47:38
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why not discussing c=-1, 13, or -13
-DCH-
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10/24/2016 postreply
16:52:16
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有道理啊,难道我说的没道理吗,三次方程和直线,为什么会没交点?
-一九得九-
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10/24/2016 postreply
14:36:56
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俺 做错了,改过来了
-skyport-
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10/24/2016 postreply
14:40:28
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谢
-一九得九-
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10/24/2016 postreply
14:43:41
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奇怪。c=0 x=13 不行吗?
-YuccaPalm-
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10/24/2016 postreply
14:51:44
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