P(X) 可以被(x-c) 整除,那么,p(x)=k(x-c) 没错啊。
就是:
y = x(x-a)(x-b)-13
y = k(x-c)
交点
P(X) 可以被(x-c) 整除,那么,p(x)=k(x-c) 没错啊。
就是:
y = x(x-a)(x-b)-13
y = k(x-c)
交点
•
楼下的尔思的解是完整解
-backyardfun-
♀
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10/24/2016 postreply
15:26:48
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