It's only wrong b/c you missed the context.
所有跟帖:
•
Your old defense trick again! :)
-career-
♂
(0 bytes)
()
03/06/2015 postreply
21:27:41
•
You are as right here as your "sinc(x) is NND". What a joke.
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
06:10:39
•
Yes, sinc(x) is non-negative definite, because its Fourier Tran
-career-
♂
(212 bytes)
()
03/07/2015 postreply
06:42:57
•
Bochner calls it "positive definite", not "NND". Get a better te
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
06:56:21
•
FT(sinc(x)) becomes zero at lots of points, doesn't it?
-career-
♂
(53 bytes)
()
03/07/2015 postreply
07:06:36
•
Sigh. You don't understand the proof of the Bochner Theorem. Go
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
09:05:12
•
You don't need more "proof"--it's by the definition! :)
-career-
♂
(0 bytes)
()
03/07/2015 postreply
09:15:36
•
Surprised anyway would hire someone like you who doesn't know
-weston-
♀
(78 bytes)
()
03/07/2015 postreply
09:44:02
•
You forgot any integral over a zero-valued set yields zero. :)
-career-
♂
(62 bytes)
()
03/07/2015 postreply
11:18:28
•
Your step function is not zero over an open interval. Check Four
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
11:21:46
•
It's a rectangular function--not a "step"!
-career-
♂
(67 bytes)
()
03/07/2015 postreply
11:33:18
•
Wikipedia "rectangular function, the next simplest step function
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
11:40:53
•
hoho, you even need Wiki for that! :)
-career-
♂
(168 bytes)
()
03/07/2015 postreply
11:46:47
•
For your conenience only, since you had idea step functions cove
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
11:57:00
•
I have the rectangular. it is you who "mis"-"step":)))
-career-
♂
(567 bytes)
()
03/07/2015 postreply
11:59:34
•
你这是 "白马非马" 的现代版
-weston-
♀
(0 bytes)
()
03/07/2015 postreply
12:03:16
•
Stay in math,pls. :)
-career-
♂
(0 bytes)
()
03/07/2015 postreply
12:19:30