中!

来源: nj_guy 于 2011-11-11 12:03:03 [档案] [博客] [旧帖] [给我悄悄话] 本文已被阅读：次 (1204 bytes)

回答: A proof 由 BeLe 于 2011-11-11 00:21:43

bsically if we have an estimation for Chebyshev constant with:

pi(x) < C x/ln x

then pi(x) * ln x < C * x => x^pi(x) < (e^C)^x.

So we need to show 2*ln2 = 1.38629436+ is a good Chebyshev constant. Actually, there are proofs that 1.256 is a good Chebyshev constant.

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